1. It is known that the equation of x and y is 3x+y = 2+3m; For the solution of x+3y=2-3m, both x and y are positive numbers. Find the value range of m.

Solve the equations about x and y

3x+y=2+3m

x+3y=2-3m

Get:

x=( 1+3m)/2

y=( 1-3m)/2

The answer is positive.

x =( 1+3m)/2 & gt； 0， 1+3m & gt； 0，m & gt- 1/3

y =( 1-3m)/2 & gt； 0， 1-3m & gt； 0，m & lt 1/3

Value range of m:-1/3.

3. The set of known inequality X-3 (X-2) ≤ 4; (a+2x)/3 & gt； The solution set of x- 1 is1≤ X.

x-3(x-2)≤4

x-3x+6≤4

3x-x & gt； =6-4

x & gt= 1

a+2x/3 & gt； x- 1

a+2x & gt； 3x-3

x & lta+3

So 1 ≤ x

The solution set is1≤ x.

So a+3=2.

a=- 1