The first alloy: zinc: copper: nickel = 2: 3: 1 = 4: 6: 2.
The second alloy: zinc: copper: nickel = 2: 4: 3 = 4: 8: 6.
The first alloy: Zn: Cu: Ni =1:2:1= 2: 4: 2.
Another alloy: zinc: copper: nickel = 10: 18: 10.
Each serving: (10+18+10)/(4+6+2+4+8+6+2+4+2) =1(g)
The first alloy is 1x(4+6+2)= 12 (g).
The second alloy is 1x(4+6+8)= 18 (g).
The third alloy is 1x(2+4+2)=8 (g).
Someone rode a bicycle from place A to place B, and at first, he drove at the speed of 18km per hour. When the remaining distance was 32 kilometers less than the distance he had traveled, he began to walk the remaining distance at a speed of 25 kilometers per hour. If the average speed of the whole journey is 20km per hour, how to find the distance between A and B?
Solution: Let the remaining distance be X kilometers and the driving distance be x+32 kilometers.
x/25+(x+32)/ 18 =(x+x+32)/20
36x+50(x+32)=45(2x+32)
36x+50x+ 1600 = 90x+ 1440
4x= 160
x=40
Distance between Party A and Party B: 40+40+32= 1 12 (km).
15.5-0.4(x+3)= 3/4x-2/5(x-5)
15.5-0.4x- 1.2 = 3/4x-2/5x+2
3/4x= 12.3
x= 16.4