Current location - Training Enrollment Network - Mathematics courses - Math problem: For a cup of salt water, the ratio of salt to salt water is 1: 5. After adding16g of salt, the ratio of salt to salt water is 1: 4. How many kilograms of salt water are there?
Math problem: For a cup of salt water, the ratio of salt to salt water is 1: 5. After adding16g of salt, the ratio of salt to salt water is 1: 4. How many kilograms of salt water are there?
The water quality is constant.

Originally, salt accounts for water =1÷ (5-1) =1/4.

Now salt accounts for water =1÷ (4-1) =1/3.

Water =16÷ (1/3-1/4) =192kg.

Salt = 192× 1/4 = 48kg.

Raw brine = 192+48=240 kg.

You can ask questions if you don't understand. If it helps, please adopt it. Thank you!

Related articles
  • Experience and methods of preparing for the exam in senior three.
  • How to enter chemical equations in word
  • Comparison table of mathematical arithmetic and geometric series knowledge in senior one.
  • Which is better for Shanghai SAT training basic class?
  • Is it difficult to divide the high school mathematics training course into one volume?
  • How to judge true proposition and false proposition
  • Winter vacation life's instruction: winter vacation homework's answer to the fourth grade mathematics in primary school.
  • What is the game of the stock market and the chess game of the four countries?
  • How to teach math well?
  • A problem in the math exercise book of senior one in the new curriculum standard

    • copyright 2024 Training Enrollment Network All rights reserved