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Angle shift problem of mathematical trigonometric function
From the topic b≠0, the equation of the straight line L is 2x+by- 1=0, and it is changed to y =-(2/b) x+1/b.

Because the equation of the straight line L is 2x+ times-1=0. The dip angle is a, ∴ Tanner =-2/b.

( 1)∵π/6

Tan(π/6) or tana

(√3)/3 or Tana

So-2/b > (√3)/3 or -2/b

, that is, -2 √ 3

1 or b

∴0<; 1/b< 1 or-1/2

Or 0

∴-2

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