1. The amount of water overflowed from the container: the volume of the first ball, the second ball-ball, and the third ball+ball-ball.

Let the volumes of small ball, middle ball and big ball be x, y and z respectively, then

X=(Y-X)/3, that is, Y=4X.

X+Z-Y=2.5X, namely Z= 1 1X/2,

So x: y: z =1:(4): (11/2) = 2: 8:11.

2. Percentage of old workers: (600 *% 5+400 * 20%)/(600+400) =11%;

A group of old workers should be transferred: 400*(20%- 1 1%)=36 people.

perhaps

Old workers of Team A: 600× 5% = 30.

Old workers of Team B: 400× 20% = 80.

There are old workers in the two teams: 30+80 = 1 10 (people).

The ratio of the total number of people in the two teams is 600 ∶ 400 = 3 ∶ 2.

To make the proportion of old workers in the two engineering teams of Party A and Party B the same, the proportion of old workers in the two teams should also reach 3: 2.

After adjustment, the old workers of Team A: 1 10 ÷ (3+2) × 3 = 66 (person)

Number of young workers in Team A exchanged with old workers in Team B: 66-30 = 36 (persons)