(1)AD is the angular bisector, so AC/AB=CD/BD= 1.5/2.5=t, so AC= 1.5t, AB=2.5t, (1.5t) 2+4.

(2) Point O is the intersection of bisectors of three angles ∠ A, B and C, so OD=OE=OF=t, so (6+8+ 10)t=6*8,

So t=2, so the distance from point O to three sides AB, AC and BC is equal to 2 respectively.