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The grand finale of the first grade math problem (solved by the first grade method! )
You did something wrong. When 0≤x≤5, P(5-x, 0)Q remains unchanged (0, 10+x).

P (x-5,0) q (0, 10+x) when 5≤x≤ 10.

B.△APQ in the process of movement, its area is always AP×OQ/2.

The area of ∫△APQ is 32 square units.

∴AP×OQ=64

∫AP = 10-x OQ = 10+x

∴( 10-x)×( 10+x)=64

X=4 times the root number 2 (minus)

C first, when x=2, let's calculate the area of △APQ, and S△APQ=48.

After that, △AQE can be based on QE and OA is high.

∴QE×OA/2=48 QE×OA=96

OA = 5

∴QE= 19.2

Note that QE is the length, and there should be two E points in the coordinate.

∴e(0,3 1.2)(0. 1.6)