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The most difficult math problems and answers
Because △ABC and △DBC have the same cardinal number and the same height.

So their areas are equal.

So the area of △AOB is equal to the area of △COD.

So the area of delta delta △AOB is 6.

Because the OB of △COD and △COB is equal to the height of OD side.

So their area ratio is equal to the bottom ratio.

So the ratio of OD and OB is 6: 12 = 1: 2.

Because OB of △AOD and △AOB is equal to the height of OD side.

So their area ratio is equal to the bottom ratio.

Therefore, the ratio of △AOD to △AOB is equal to the ratio of OD to OB = 1: 2.

So the area of △AOD is equal to half the area of △AOB = 3.

So the areas of the other two triangles are 3 and 6 respectively.

Junior high school knowledge answer:

Because s △ OCD: s △ OCB = OD: OB

So OD/OB = 6/ 12 = 1/2.

Because AD//BC

So △AOD∽△COB

So s △ AOD: △ COB = (OD/OB) 2 = 1/4.

So s △ AOD: 12 = 1/4.

So s △ aod = 3.

Because s △ AOB: △ Cob = OA/OC = OD/OB.

So s △ AOB: 12 = 1/2.

So s △ AOB = 6

So the areas of the other two triangles are 3 and 6 respectively.

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