Let the train speed be one meter per second and the car body length be b meters.
1 min =60 seconds
60a= 1000+b
40a= 1000-b
100a=2000
A = 20m m/s
b=60x20- 1000
B=200 meters
It is 200 meters long. The vehicle speed is 20m/s.
12, Party A and Party B run on the circular road at a constant speed, if they start at the same time. Walk in opposite directions and meet every 2 minutes; If you go in the same direction, meet every 6 minutes. It is known that A runs faster than B. How many laps do A and B run per minute?
Solution: Let A run X laps per minute and B run Y laps per minute. According to the meaning of the question in the equation:
2X+2Y= 1
6X-6Y= 1
X = 1/3 and Y = 1/6 are obtained.
A: A runs 1/3 laps per minute, and B runs 1/6 laps per minute.