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Eighth grade math. A functional problem! Somebody teach me! I'm in a hurry! (It's better to have a process)
1.

∫Y = X+2-3b is a proportional function.

∴2-3b=0

The solution is b= two thirds.

2.

Line Y=2009X+2008

Y increases with the increase of x

The bigger x, the bigger y.

So y2 is greater than y 1.

3.

∫ The image of function Y=mx-(4m- 1) passes through the origin.

∴-(4m- 1)=0

The solution is that m= one quarter.

This function is a proportional function.

4.

∵ The image of linear function is parallel to the straight line y=-x+ 1.

∴k=- 1

Too many (8, 2)

∴2=- 1×8+b

The solution is b= 10.

The resolution function is y=-x+ 10.

5.

The straight line y=kx+b is parallel to the straight line y=-3x+4.

∴k=-3

The intersection of ∵ and the straight line y=2x-6 is on the X axis.

Substitute y=0 into y=2x-6 to get x=3.

Substitute the point (3,0) into y =-3x+b.

Get b=9.

The resolution function is y=-3x+9.

6.

Judging from the meaning of the question: -3k+b=-5.

6k+b=-2

The solution is k= one third and b=-4.

So the resolution function is y= one third x-4.

7.

Y decreases with the increase of X.

When x is small, y is large.

∴ when x 1 is greater than x2.

Y 1 is less than y2.

I finally understand ~ I am also a junior two student.