The center of the circle is (0,0), so d= 1/ (2 under the root sign) = (2 under the root sign)/2.
2.y' = 6x2, tangent slope k=6* 1=6.
The tangent equation is Y=6(X- 1)+3, which is simplified to 6X-Y-3=0.
3. Let the expression of this function be ax 2+bx+c = 0 (1), because it spans points (0,0) and (-4,0).
So C=0,
16A-4B=0,B=4A,
So the formula (1) can be simplified as ax 2+4ax = 0, and further simplified as x 2+4x = (x+2) 2-4 = 0.
So the equation of symmetry axis is X = -2.
Hope to adopt ~