Solution: Given that the difference between the product of two larger numbers and the product of two smaller numbers is a, then:

(n ^ 3)(n ^ 2)-(n ^ 1)n = A

∫(n ^ 3)(n ^ 2)=(n ^ 1 ^ 2)(n ^ 2)=(n ^ 1)n ^ 2(n ^ 1 ^ n)4

∴(n 3)(N2)-(n 1)n = 2(n 1n)4 = 4n 6 = a

You can get ∴ n=(A-6)/4.

You can find the smallest number: n

Therefore, it can be concluded that n, n 1, n2 and n3 are four continuous natural numbers.

(I hope to adopt it, thank you)