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An additional problem in mathematics
A * * * took out (1+12) *12 = 78 eggs.

If both are 50g, a * * * weighs 78 * 50 = 3900g.

Now it weighs 10 gram.

Every time you replace 50 grams of eggs with 47 grams of eggs, you lose 3 grams.

Every time 50 grams of eggs are replaced by 55 grams of eggs, it weighs 5 grams.

The front should be the same, not an equation, right!

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Those that weigh 5 grams and those that weigh 3 grams are also 10 grams.

3*5= 15

So three 5-gram weights and five 3-gram light weights together offset the weight.

Put two more 5g, which is exactly10g.

But in this way, there are two boxes with five, and it will not stand.

15*2=30

So six 5g and 10 3g are put together to offset the weight.

Put two more 5g, which is exactly10g.

In this way, the weight of 5 grams is taken as 8 grams, and the weight of 3 grams is taken as 10.

47 grams of eggs are in 10 box.

55 grams of eggs are in the eighth box.