+│ │ b │+c │ = 1, find the value of abc │ │abc│.

A │a│+│b│ b+c │ C = 1, then there are two positive numbers and one negative number in A, B, C, B and C.

So ABC

therefore

Abc score │abc│=abc score -abc=- 1

Let a.b.c be a nonzero organic number, and try to find a │a│+│b│ b+c │c│+│abc│. .................. should be abc │abc│! ! !

If the numbers A, B and C are all positive numbers, the above formula =1+1+1= 4;

If two of the three numbers A, B and C are positive numbers, the above formula =1+1-1= 0;

If one of the three numbers A, B and C is a positive number, the above formula =1-1-1+1= 0;

If the numbers A, B and C are all negative, then the above formula =-1-1-1-1=-4.

(2) Please add appropriate conditions to A and B in │a+b│=a+b to make the equation hold.

A+b is greater than or equal to 0.

(3) Arrange the following figures in descending order:

- 1 1. 12. 1 1. 13. 14- 13. 12-265438+22.0.

- 1 1. 12

(4) Because │a│ has a minimum value, is there a minimum value when X is a rational number │ X- 1 │+X+ 1 │? If yes, find the minimum value; If not, explain why.

When x is between-1 and 1, │x- 1│+│x+ 1│ has a minimum value.

The minimum value is 2.

(5) There are several numbers, the number of 1 is marked as A, and the second number is marked as a2 (in fact, 2 is below and A is above); The third number is a3 ... The nth number is one. If a 1=- 1, each digit of the second digit is equal to the reciprocal of the difference between 1 and its previous digit.

{1}. Trial calculation: a2=(-2), a3=(-3), a4=(-4).

{2}. According to the above calculation results, please write A2009 = (-2009), A20 10 = (-20 10), An = (-n) (n is a positive integer greater than 1).