(2) Because the angle A 1FE= Angle A 1FE 1- Angle EFE 1=90-60=30 degrees.

EF=BF=5, so FG=COS30 times the root number 3 of EF=2 times 5.

(3) Because these two triangles are congruent triangles, AF = FDEF = FB1AF-EF = FD-FB1.

AE=B 1D, angle HAE= angle HDB 1=30 degrees angle AHE= angle DHB 1.

So the triangle AEH is equal to the triangle db1h.

So AH=DH

There are many methods, which may not be the simplest.