1. It is known that f(x) is an even function and a decreasing function on [0, positive infinity]. if f(lgx)>； F( 1), then the value range of x is

F (x) is an even function.

∴ f (-x) = f (x) = f (| x |) .........................................................................................................................................

F (lgx) > f (1) can be changed to f (| lgx |) > f (1),

It is a decreasing function on [0, +∞)

∴|lgx|<； F( 1), i.e.-1< lgx <; 1

The solution is x ∈ (110,10).

2. Given that the three vertices of △ABC are A (1, 3/2), B (4 4,2), C (1, Y) and the center of gravity is G(x,-1), then the values of X and Y are respectively

x=( 1+4+ 1)/3=2

- 1=( 1.5-2+y)/3

y=-2.5

Gravity center formula: the abscissa of gravity center is the sum of abscissa of three vertices of triangle divided by 3.

Same ordinate