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20 14 how to solve the math problem of Tianjin senior high school entrance examination 17?
Analysis: Let ∠△DCE=x and ∠ACD=y, then ∠ACE=x+y, ∠ BCE = 90-∠ ACE = 90-X-Y, and get ∠ ACE = ∠ according to the equilateral corners.

Answer:

Solution: Let ∠DCE=x and ∠ACD=y, then ∠ACE=x+y, ∠ BCE = 90-∠ ACE = 90-X-Y. 。

AE = AC,

∴∠ACE=∠AEC=x+y,

BD = BC,

∴∠bdc=∠bcd=∠bce+∠dce=90-x-y+x = 90-y

In △DCE, ∫∠DCE+∠CDE+∠DEC = 180.

∴x+(90 -y)+(x+y)= 180,

X = 45,

∴∠DCE=45。

So the answer is: 45.