A math problem. Note ... there are two situations.
We know that the volume of a cylinder with equal base and equal height is three times that of a cone. If the volumes are equal and the bottoms are equal, the height of the cone is three times that of the cylinder. Now the height of water in the tank is a quarter of its original height. Water is poured into the awl, and the volume remains the same. So the height should be three times the height in the cylinder. 4X 1/4 X3=3, so the water level in the cone is 3.