Mathematics Resources and Evaluation of Grade Eight/KOOC-0/Exploring Pythagorean Theorem (II)/KOOC-0/3/KOOC-0/4/KOOC-0/5/KOOC-0/6/KOOC-0/7/KOOC-0/8 Answer
The intersection D makes DE perpendicular to nAB, intersects with fAB at point C, and E is 8: DC = DE = 2 in RT TRI-N polygon. 8 (the distance between the point R on the bisector of the angle and both sides of the angle is equal), BD=0. 8, so 0BE=3 BE. DE=BC .AC (6 six situations are similar to the corresponding sides of a triangle), so 0ac = 62011-kloc-0/0-3017: 56:19.