Replace n 2 with 3+n (because N2-n = 3;; N 2 = 3+n), then the original formula is equal to
2(3+n)-Mn+2m+20 16 = 2(m+n)-Mn+2022
According to Vieta's theorem (for the relationship between roots and coefficients, we might as well first identify m=x 1, n=x2).
Mn=-3, m+n= 1, (only a pair of unique answers)
Original formula: 2* 1+3+2022=2027.