The key to solving engineering problems is to regard the total workload as "1". In this way, work efficiency is the reciprocal of working hours (it represents a fraction of the total amount of work completed in a unit time), and then formulas can be listed according to the relationship among workload, work efficiency and working hours.

1, workload = working efficiency x working time.

2, working hours = workload ÷ work efficiency.

3. Working hours = total workload ÷ (A working efficiency +B working efficiency).

Engineering problems mainly study the relationship among workload, work efficiency and working hours. Under the known conditions, this kind of problems often do not give specific quantities, but only put forward "a project", "a piece of land", "a canal" and "a work". The unit "1" is often used to express the total workload when solving problems.

A case study on solving engineering problems by applying math problems in grade six.

Example: A batch of parts will be completed in 6 hours by Party A and 8 hours by Party B.. Now two people work together to complete the task. A has done 24 more than B. How many parts are there?

Think about solving problems:

Let the total workload be 1, then Party A will finish 1/6, Party B will finish 1/8, and Party A will finish more than Party B (1/6- 1/8). When two people work together, they will finish every hour (/kloc-0) Because it takes (1÷ (1/6+1/8) hours for two people to work together, during this time, A made 24 more parts than B.