(Then, because only two sets of 8 and 10 can form 36, write it in any middle box, because the middle box only involves two sets of horizontal and vertical, regardless of the hypotenuse, and then you can find the corresponding space according to the sum of 36. )
What's the last remaining figure? 13, 15,9, 1 1 these four numbers, because 8, 13,15 can add up to 36, so because the middle left is 14, and the right is. You can rotate the graph clockwise or counterclockwise to get graphs with different positions, but they are all deformed from one graph and can all become like this, and this graph can also become other shapes)