2. Answer: There are only three situations (bird 12, bird 23 and bird 13), so the probability of having two males is 3 * (1/2) 2 * (1/2) = 3/8.

3.( 1)2/6 (the probability of the first to take out the yellow ball) *3/6 (the probability of the second to take out the yellow ball) = 1/6.

(2) A. The probability that the first one takes out the yellow ball and the second one takes out the white ball: 2/6*3/6= 1/6.

B The probability that the first one takes out the white ball and the second one takes out the yellow ball: 4/6*3/6= 1/3.

Then the probability that there is a white ball and a yellow ball among the two balls taken out is1/6+1/3 =1/2.

The process is detailed enough. This is a simple question!

If you still don't understand, hi me.

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