B=A+A+A
Looking for a = B=？
Solution: Number two equations:
A+B=24( 1)
B=A+A+A(2)
Replace b in formula (1) with 3 A in formula (2).
Get a+a+a+a = 24.
So a = 6 and b = 18.
I hope I can help you. Don't ask me again.
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○+mouth =9 1△+ mouth =63 △+○=46 Equivalent substitution in elementary mathematics ○+△+mouth = 9 1+63 △+2 * mouth = 154 △+○=46 46+2*.
An elementary school math application problem 0.035-18.5 =16.5 (kg)
Pear: 16.5x2=33 (kg)
Basket: 35-33=2 (kg)
In fact, it is very simple: first look at the sentence "the basket weighs 18.5kg after taking out half". It says that half of it is18.5kg. If you know half of it, you can know a * * *, and you can know a * * *. If you subtract the weight of pears from the weight of pear baskets, that's all! Come on, study math well! Glad to answer for you!
Replace 600 rabbits with equivalent math problems. Wow, that's too much.
2 cows =8 pigs, 1 cow =4 pigs, 5 cows =20 pigs.
3 pigs =9 sheep, 1 pig =3 sheep, 20 pigs =60 sheep.
2 sheep =20 rabbits, 1 sheep = 10 rabbits, 60 sheep =600 rabbits.
Questions and Answers on Mathematics Application in Primary Schools: Wen Ku. Baidu, please. /view/5935 BFF 3f 90 f 76 c 6 137 1 a5。
Elementary school math application problem, speed! The topic of high score is not very rigorous, 1× clothes 36 yuan/piece, 1× shoes 24 yuan/pair, 6× gloves 6 yuan/pair. 1× socks 3 yuan/pair, and there are many answers.
Primary school mathematics application problems, set unknown solutions;
Suppose the cock keeps X and the hen keeps X (1.5x+300).
x+ 1.5x+300=4800
2.5x=4500
x= 1800
Number of hens =1.5 *1800+300 = 3000.
Answer: Rooster and hen have 1800 and 3000 respectively.
What is the primary school mathematics application problem network: xxsx. /mainmenu.aspx
Can primary school math application problems be listed as equations? As long as the problem does not require arithmetic methods, equations can be used.
Innovative training of mathematical application problems in primary schools 1260- 1260 divided by six fifths =2 10 hectare.
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