According to "all to Party A and Party B, at least one piece for each person", the answers need to be classified:

( 1) A 1，B 4。

A. If Party A is given 1 and Party B is given 1, 2, 3, 4, there is only the method of 1.

B. If what is given to Party A is not 1, Party A can choose 1 from 2, 3 and 4, give it to Party A C3 1=3, and give the rest to Party B..

* * * There are 3+ 1=4 methods.

(2) Party A has 2 copies and Party B has 3 copies.

A. If one of the cards given to Party A is 1, you should choose 1 from 1, 2, 3 and 4 to give it to Party A. There are four ways. (including the case that A has two 1)

B. If 1 is not given to Party A, Party A can choose two of 2, 3 and 4 to give to Party A C32=C3 1=3, and give the rest to Party B. ..

* * * There are 4+3=7 methods.

(3) 3 copies for Party A and 2 copies for Party B.

A. If one of the cards given to Party B is 1, you should choose 1 from 1, 2,3,4 and give it to Party B C4 1=4. There are four ways. (including the case that A has two 1)

B. If 1 is not given to Party B, Party B can choose two of 2, 3 and 4 to give to Party B C32=C3 1=3, and the rest to Party A. ..

* * * There are 4+3=7 methods.

(4) Party A 4, Party B 1

A, if you give B 1, then give A 1, 2, 3, 4, and there are only 1 methods.

B. If it is not 1 for Party B, you can choose 1 from 2, 3 and 4, where C3 1=3 is for Party B and the rest is for Party A..

* * * There are 3+ 1=4 methods.

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A * * * has 4+7+7+4=22 points.