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A math problem. Seeking process.
If you have a junior high school education or above, use the binary linear equation as follows:

Solution: suppose the cow is X yuan and the sheep is Y yuan.

5X+2Y= 10

2X+5Y=8

Solution: X=34/2 1

Y=20/2 1

If you have no junior high school education or above, use this method:

10+8 =18 (price of 7 sheep and 7 cows)

1 8 ÷ 7 =18/7 (1price of sheep and1price of cattle)

5 cows and 2 sheep should be 10 yuan.

Then the price of three cows: 10-( 18/7×2)=34/7.

So the price of a cow: 34/7÷3=34/2 1

Similarly, we can get the price of three sheep: 8-( 18/7×2)=20/7.

So the price of a sheep is 20/7÷3=20/2 1.

Expect to adopt with pure hands

Finally, I hope to check whether the topic is misspelled. The data is too complicated.