The first question:

According to sine theorem:

2√3/sinA=2√2/sin45

sinA=2√3×√2/2 ÷2√2

Sina =√3/2

So a = 60 or 120.

When a = 60, c = 75. In the same way, we can get c=√6+√2.

When a = 120, c = 15 and C=√6-√2.

Question 2: a=3, b=√3, A = 60.

According to sine theorem:

3/sin60 =√3/sinB

sinB=√3×√3/2 ÷3= 1/2

Therefore, b = 30 (150).

Then c = 90.

3/sin60 =c/sin90

c=3× 1÷(√3/2)=2√3