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Math problems in the sixth grade of primary school
1.(4000-800)× 14%+(5000-4000)× 1 1%=448+ 1 10=558

Mr Zhiyi is paid more than 800 yuan.

If the remuneration exceeds 800 yuan but not more than 4,000 yuan, the remuneration shall be set at X yuan.

(x-800)x0. 14=434 ∴x=3900

If the remuneration is higher than 4000 yuan, 434/0. 1 1 = 3946 yuan < 4000 yuan ∴ does not matter.

All in all, I got a reward of 3900 yuan.