Question 1: if m is the midpoint, then b (2,5 5) P is the intersection of the center of gravity and three high lines, then p is the midpoint of BC, and if c (x,2) is x=6, then c (6,2) is two points (3,2 2) B (2 2,5) and c (6,2).

Question 2: Let A(- 1, 2) and the symmetry point B(a, b).

Then AVB vertical y=x- 1 in the middle, on a straight line.

Y=x- 1 slope is 1.

So AB slope (b-2)/(a+ 1)=- 1.

a+b= 1

AB midpoint (b+2)/2=(a- 1)/2- 1.

a-b=5

So a = 3 and b =-2.