∴DE⊥CB,CD=DB

∴∠BED=∠A=90，∠C=∠DBE

Bd is the bisector of ∠ABC.

∴∠DBE=∠ABD

DB = DB

∴△ADB≌△EDB

∴∠DBA=∠DBE

∠C+∠DBE+∠DBA+90 = 180

∠C=30