Problem description:

Change 8 (decimal) into binary.

Convert 15 (decimal) to binary.

Convert 0.45 (decimal) to binary.

Convert 27.75 (decimal) to binary.

Change1011kloc-0/(binary) to decimal!

Analysis:

Using the rounding method, you can:

8/2=4+0

4/2=2+0

2/2= 1+0

1/2=0 remainder 1

So the binary of 8 is 100.

15/2=7 remainder 1

7/2=3 remainder 1

3/2= 1 remainder 1

1/2=0 remainder 1

So the binary of 15 is111.

0.45×2=0.9 Integer part 0 Decimal part 0.9

0.9×2= 1.8 integer part 1 decimal part 0.8

0.8×2= 1.6 integer part 1 decimal part 0.6

0.6×2= 1.2 integer part 1 decimal part 0.2

0.2×2=0.4 Integer part 0 Decimal part 0.4

0.4×2=0.8 Integer part 0 Decimal part 0.8

0.8×2= 1.6 integer part 1 decimal part 0.6

......

So the binary of 0.45 is about 0.0111001.

27/2= 13 1

13/2=6 remainder 1

6/2=3+0

3/2= 1 remainder 1

1/2=0 remainder 1

0.75×2= 1.5 integer part 1 decimal part 0.5

0.5×2= 1 integer part 1 decimal part 0

So the binary of 27.75 is1101.11.

10 1 10 1= 1×2^5+0×2^4+ 1×2^3+ 1×2^2+0×2^ 1+ 1×2^0

=32+0+8+4+0+ 1

=45

Therefore, the decimal system of1011is 45, where 2 5 means 2 to the fifth power (because the keyboard is difficult to type mathematical expressions, it can only be like this, and it can be changed when writing.