Note: X in the solution is not a multiplication sign, I use * to represent the multiplication sign.

The answers are as follows: Mi represents the number of type I scheme machines (0- 1 variable), and Xij represents the time taken by type I scheme machines to produce J-shaped wire rod (unit: thousand hours) (I = 1, 2,3,4,5; j= 1，2)

Expenses (all in thousand yuan) include: annual depreciation expense of newly purchased and improved equipment (0500 yuan), annual fixed expense of equipment (f), annual operating expense (r) and waste loss (l), among which:

K=200 M2+ 100 M4+500 M5

f = 30m 1+50 M2+80 M3+ 100 M4+ 140 M5

r = 5(x 1 1+x 12)+7(x 2 1+X22)+8(x 3 1+X32)+8(x 4 1+X42)+ 12(x 5 1+X52)

The annual waste loss of equipment 1 is 0.030 * 0.02 * (1000x11+800x12) = 0.6x1+0.

l = 0.6x 1 1+0.48 x 12+0.9x 2 1.8x 22+ 1.8x 3 1.5x 32+2.4x 4 1+ 1.95 x42+2.4x 5 1

The optimization objectives are

min 0.05k+F+R+L = 30m 1+60 m2+80 m3+ 105 M4+ 165 M5+5.6x 1 1+5.48 x 12+7.9x 2 1+7.84 x22+9.8x 3 1+9.5x 32+65438+

Constraints include:

1) meets the demand: bare copper wire can not only be directly supplied to the market, but also be used as a semi-finished plastic packaging machine to produce plastic-coated lines, so the demand for bare copper wire (specification1200x31+1600x41) is 3000+65438. Bare copper wire (specification 1) is produced by equipment 1, 2. Considering the waste loss, it should be 0.98 * (1000x1+1500x21) > = 3000+1200x31.

980 x 1 1+ 1470 x 2 1- 1200 x 3 1- 1600 x 4 1 & gt； =3000

similarly

784 x 12+ 1372 x22- 1000 x32- 1300 x42 & gt； =2000

1 164 x 3 1+ 1552 x 4 1+ 1552 x 5 1 & gt； = 10000

970 x32+ 126 1x 42+ 1 164 x52 & gt； =8000

2) limitation of machine productivity: each machine can only work for 8000 hours at most every year, that is to say,

Xi 1+Xi2 & lt； =8Mi (i= 1，2，3，4，5)

3) Limitation on the number of existing production equipment:

M 1= 1

M3+M4= 1

4) Variable range limitation: Mi is 0- 1 variable, and Xij is non-negative.

Using LINGO to solve the problem: 1 II wire drawing machine and combination machine need to be purchased newly, and the plastic sealing machine does not need to be modified; The corresponding task assignment can be obtained from the value of Xij; The total cost is 574,000 yuan.