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Put the ball in the combined math box.
Different balls: 1 box can be empty: m n (each ball has m boxes to choose from); The box can't be empty and complicated, and it can be discussed according to the specific quantity.

The same ball: 1 box cannot be empty: the baffle serves n balls continuously, and is divided into m boxes by (m- 1) baffles. There is one method in C(n- 1)(m- 1); 2. The box can be empty: replace the baffle with elements and regard the baffle as a small ball, so select * * (n+m- 1) elements and put the baffle at (m- 1) positions * * c (n+m-1) (m-)

Very abstract. Understand for yourself.