I. 1, -3℃
2, 2 or -4
3, rational number subtraction rule A-B = A+(-B)
4, 2
5. The answer is not unique. For example, 0.5x= 1.5.
6. Fill in 0 and 5 in the second line and -0.5 in the third line.
7、 123
8、4
9.400 students' overall vision, the sample is 40 students' vision.
10、2.8
Second, 1 1, d; 12、B; 13、C; 14、D; 15、A; 16、A; 17、B; 18、C; 19、D; 20、D
Third, be careful.
1.( 1)-968; (2)y=- 1 .
2. Yuan ~ Yuan. (Note: The total length is (1 min) km;
The scheduled fare is calculated in RMB/km, and the fare is
The scheduled fare is calculated in RMB/km, and the fare is
That is, the fare range is yuan ~ yuan. )
3. Complementary angles of (1) and ∠AOD ∠BOD, ∠COD
The angles ∠AOE and ∠COE are complementary to ∠BOE.
(2)COD+∠COE =∠AOB = 90。
Tip: Because OD divides ∠BOC equally, ∠COD= ∠BOC.
And OE shares ∠AOC equally, so ∠COE= ∠AOC,
so∠COD+∠COE =∠BOC+∠AOC =∠BOC+∠AOC),
So ∠ COD+∠ COE = ∠ AOB = 90.
4.( 1) ; 1,4,6,4, 1;
(2) , .
5.( 1) 1500m; (2)6825.6 yuan
6.( 1)400 meters
Tip: Suppose the distance between this city and a city is X kilometers.
According to the question, 200? + 15x+2000=200? +20x+900- 1 100
Solving this equation gives x=400.
(2) When the total cost of trains and cars is the same, there are
.
Solve this equation and get s= 160.
That is, when the distance between this city and a city is greater than 160 km, it is more economical to choose train transportation;
When the distance between this city and a city is equal to 160 km, you can choose two modes of transportation: train and car.
When the distance between this city and a city is less than 160 km, it is more economical to choose car transportation.