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Mathematical similarity of grade three
Solution: Because the triangle CDE is an equilateral triangle, CD=CE=DE, and because DE * DE = AD * EB and DE/EB = AD/DE, CE/BE=AD/CD, the triangular ADC is similar to the triangular CEB, so AC/BC=AD/CD=CE/BE, so the triangular ACB is similar to the triangular ADC and similar to the triangular ADC.