(1) three numbers do not contain 0 and 5, that is, 0 and 5 cannot appear, which means 3,56 kinds of 8, accounting for 56/120 = 7/15;

(2) Three numbers do not contain 0 or 5, that is, one of 0 and 5 can appear, but not both, so you only need to remove them all, that is, choose 1 from 8, so it is (120-8)/120 =14/650.