Cyclic decimal 1.2360360 ... The number in the decimal part 20 14 is the fifth order of the formula.
This problem mainly examines the remainder problem. First of all, we can see that the cyclic number is 360, so we can use 20 14-2 to get 20 12 (which means removing the first two acyclic numbers), and then use 20 12/3 to get the remainder of 2, which means the final answer is 6.