The analytical expressions of 1, point A 1( 1, 1) and a2 (7/2,3/2)-straight line A 1A2 can give y = 1/5x+4.

2. Connect the diagonals of squares A 1C 1, A2C2 and A3C3 ... In order to get triangles MA 1C 1, MA2C2 and MA3C3 ... are similar ... If the diagonals of squares are equally divided (let A3C3=B2B3=2x), then

3. From the ordinate of A 1, A2, A3 ... (1, 3/2, 9/4 ...), we can get the (n- 1) power of (3/2) law.

4. The abscissa can be obtained from y= 1/5x+4/5.