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The complete set of all equations in junior high school mathematics.
Indirect collocation method is used to solve the quadratic equation of one variable: the known and unknown are separated first, and then factorization is carried out. The adjustment coefficient is reciprocal, and the sum-difference product sets the identity. Complete square constant, indirect formula is superior.

1 multiplication and factorization of all equations in junior high school mathematics;

a2-b2=(a b)(a-b)

a3 b3=(a b)(a2-ab b2)

a3-b3=(a-b)(a2 ab b2)

Trigonometric inequality:

|a b|≤|a| |b|

|a-b|≤|a| |b|

| a |≤b & lt; = & gt-b≤a≤b

|a-b|≥|a|-|b|-|a|≤a≤|a|

All formulas for solving equations in junior high school mathematics 2. Solution of quadratic equation in one variable;

-b √(b2-4ac)/2a-b-b √(b2-4ac)/2a

Relationship between root and coefficient

X1x2 =-b/ax1* x2 = c/a note: Vieta's theorem.

Discriminant b2-4a=0 Note: The equation has two equal real roots.

B2-4ac >0 Note: The equation has real roots.

B2-4ac & lt; 0 Note: The equation has multiple yokes.

A complete set of equations -3 formula method in junior middle school mathematics

First, we should judge how many roots there are in a quadratic equation by the discriminant of the roots of δ = B2-4ac.

1. When δ = B2-4ac

2. When δ = B2-4ac = 0, x has two identical real roots, namely x 1=x2.

3. When δ = B2-4ac >; When 0, x has two different real roots.

When the judgment is completed, if the equation has roots and can belong to two situations, the equation can be based on the formula: x = {-b √ (B2-4ac)}/2a.

In order to find the root of the equation

Formula method is a general method to solve the quadratic equation of one variable, and it is the key to open the key door.

All formulas for solving equations in junior high school mathematics: Daquan 4 two-angle sum formula;

sin(A B)=sinAcosB cosAsinB

sin(A-B)=sinAcosB-sinBcosA

cos(A B)=cosAcosB-sinAsinB

cos(A-B)=cosAcosB sinAsinB

tan(A B)=(tanA tanB)/( 1-tanA tanB)

tan(A-B)=(tanA-tanB)/( 1 tanA tanB)

ctg(A B)=(ctgActgB- 1)/(ctgB ctgA)

ctg(A-B)=(ctgActgB 1)/(ctg b-ctgA)