1. One tenth of 10 is equal to one percent of 1.

(B)3.5 and 3.50 are equal in size and have the same meaning

(c) The decimal 5.7964 is rounded to two decimal places, and the approximate value is 5.80.

(d) The minimum two decimal places are 0.0 1 and the maximum two decimal places are 0.99.

1, solution: c

2. The radius of a circular flower bed is 2.5 meters, and now a fence needs to be placed at the outer side of the flower bed 50 cm away from the edge of the flower bed, so the total length of the fence is (B )(π takes 3. 14).

(a)12.56m (b)18.84m (c) 9.42m (d)15.7m.

2. solution: b

3. The two trains are 200 meters long and 180 meters long, respectively, and they are going in opposite directions. On the double-track railway, the time from the head meeting to the tail leaving is 10 second. If the speed of one train is known as16m/s, the speed of another train is (d).

(a) 16m/s(b) 18m/s(c)20m/s(d)22m/s

3. Solution: D

4. In the class meeting to celebrate June 1st, students in one class hung a circle of colored lights with only four colors: green, yellow, blue and red. The arrangement rules are as follows:

Green, yellow, yellow, red, blue, red, green, yellow, yellow, red, blue, red, red …

Then, the color of the 208th lantern is (D)

(a) Green (b) Yellow (c) Red (d) Blue

4. solution: d

5.A walks much more than B, and B spends more time than A, so the speed ratio between A and B is (A).

(A) 1 1∶8(B)5∶2(C)25∶22(D)55∶40

5. Solution: A

The speed of A is (1+14) ÷1= 54, and the speed of B is:1÷ (1+10) =

So the speed of A: the speed of B = 54:101=11:8.

9. If the distance between A and B is 72km, Xiao Ming measures that the distance between A and B is 3.6cm and that between C and D is 4.55cm, then the actual distance between C and D is 7km.

9. Solution: 72×4.553.6 =9 1 (km)

10. A new operation "∞" is defined as: a☆b, if 2☆ 1, then (3 ☆ 14) ☆.

10, solution: 3.8

1 1. If a commodity is reduced by 5%, it will make a profit of 525 yuan. If it is sold at 75% off the price, it will lose 175 yuan, so the cost price of this commodity is RMB.

1 1, solution: (1) pricing: (525+175) ÷ (1-5%-75%) = 3500 (yuan).

(2) Cost: 3500× (1-5%)-525 = 2800 yuan.

Or 3500× 75%+ 175 = 2800 (yuan)

12. As shown in the figure, the side length of equilateral triangle ABC is 100 m, with A from point A and B from point B..

At the same time, start clockwise along the side of the triangle. A Walk 60 meters per minute.

B Walking 90 meters per minute, the turning delay is 10 second every time you pass a vertex.

Then B caught up with A in the second of departure.

12, solution: 250

The difficulty of this problem is that the delay when passing through each vertex is 10 second, and when B catches up with A, it will pass through 1 0 vertices more than A, which can be understood as 10 second for B to lead A..

Regardless of the turning delay time, if Party B leads Party A by 10 second, Party B will catch up with Party A: (100+60x1060 ÷ (90-60) =113 (min.

Now consider turning at each vertex: 330÷ 100=3 (times) ... 30 (meters),

* * * Time:113× 60+3×10 = 250 (seconds)

13. Calculate the following questions (4 points for each small question, *** 16 points).

( 1) (2)

= 1 12 ×4×4×6 = 6.5×23 -0.5

= 8 = 133 - 12

= 356

(3)

= 2÷0.2- 10

= 10- 10

= 0

(4)

= ( 1 14 +35 12 × 157 )÷ 154

= ( 1 14 +6 14 )÷ 154

= 152 ×4 15

= 2

14. Use an appropriate method to calculate the following questions (5 points for each small question, *** 15 points).

( 1)

= 4 1.2×8. 1+ 1. 1×(80+ 12.5)+(4 1.2+ 12.5)× 1.9

=4 1.2×8. 1+ 1. 1×80+ 1. 1× 12.5+4 1.2× 1.9+ 12.5× 1.9

=4 1.2×(8. 1+ 1.9)+ 12.5×( 1. 1+ 1.9)+ 1. 1×80

=4 1.2× 10+ 12.5×3+ 1. 1×80

=4 12+37.5+88

=537.5

(2)

= 94 + 16 13 13 - 12 ÷358

= 29 12 ÷ 1 13 ÷358

= 29 12 ×34 ×829

= 12

(3)

= 64+32+ 16+8+4+2+ 1 128 ÷(2+4+8+ 16+32+64+ 128)

= 64+32+ 16+8+4+2+ 1 128 × 1 2×( 1+2+4+8+ 16+32+64)

= 1 128 × 12

= 1256

15. "Safety education, alarm bells are ringing". For this reason, a school randomly selected 200 students in the whole school to conduct a questionnaire survey on their understanding of safety knowledge, and then summarized and analyzed them according to four categories: "very good", "very good", "average" and "poor", and drew a fan-shaped statistical chart.

(1) Complete the departmental statistical chart and calculate the number of 200 students who are "very familiar" with safety knowledge;

(2) Draw a bar chart.

Solution: 1-50%-25%-5% = 20%

200×25%=50 people

16. As shown in the figure, the side length of the square ABCD is 10 cm. Make a semicircle with CD as the diameter. E is the midpoint of the semicircle, and f is the midpoint of BC. Find the area of the shaded part in the figure (π is 3. 14).

Solution: If the parallel line with point E as AD intersects AB and G, then point G is the midpoint of AB side.

AG=GB= 10÷2=5 (cm), Ge = 10+00 ÷ 2 = 15 (cm), because F is the midpoint of BC and BF = 10 ÷.

Then the blank part s quadrilateral ABCD=S triangle age +s trapezoid BFEG

= 15×5÷2+(5+ 15)×5÷2

= 37.5+50

= 87.5 (square centimeter)

Shaded part S Yin = S Square ABCD+S Semicircle -S Quadrilateral ABCD Responder: ♀ Wings of Dreams ♀| Level 1 | 2011-4-812: 31.

Look for it in search.

1. The following statement is true (c)

1. One tenth of 10 is equal to one percent of 1.

(B)3.5 and 3.50 are equal in size and have the same meaning

(c) The decimal 5.7964 is rounded to two decimal places, and the approximate value is 5.80.

(d) The minimum two decimal places are 0.0 1 and the maximum two decimal places are 0.99.

2. The radius of a circular flower bed is 2.5 meters, and now a fence needs to be placed 50 cm away from the edge of the flower bed, so the total length of the fence is (B )(π takes 3. 14).

(a)12.56m (b)18.84m (c) 9.42m (d)15.7m.

3. The two trains are 200 meters long and 180 meters long, respectively, and they are going in opposite directions. On the double-track railway, the time from the head meeting to the tail leaving is 10 second. If the speed of one train is known as16m/s, the speed of another train is (d).

(a) 16m/s(b) 18m/s(c)20m/s(d)22m/s

4. In the class meeting to celebrate June 1st, students in one class hung a circle of colored lights with only four colors: green, yellow, blue and red. The arrangement rules are as follows:

Green, yellow, yellow, red, blue, red, green, yellow, yellow, red, blue, red, red …

Then, the color of the 208th lantern is (D)

(a) Green (b) Yellow (c) Red (d) Blue

5.A walks much more than B, and B spends more time than A, so the speed ratio between A and B is (A).

(A) 1 1∶8(B)5∶2(C)25∶22(D)55∶40

6. If the distance between A and B is 72km, Xiao Ming measured that the distance between A and B is 3.6cm, and the distance between C and D is 4.55cm, then the actual distance between C and D is 7km.

7. A new operation "∞" is defined as: a☆b, if 2☆ 1, then (3 ☆ 14) ☆.

7. Solution: 3.8

8. If a commodity is reduced by 5%, it will make a profit of 525 yuan. If it is sold at 75% off the price, it will lose 175 yuan, so the cost price of this commodity is RMB.

8. Solution: (1) Pricing: (525+175) ÷ (1-5%-75%) = 3,500 yuan.

(2) Cost: 3500× (1-5%)-525 = 2800 yuan.

Or 3500× 75%+ 175 = 2800 (yuan)

9. As shown in the figure, the side length of equilateral triangle ABC is 100 m, with A from point A and B from point B..

At the same time, start clockwise along the side of the triangle. A Walk 60 meters per minute.

B Walking 90 meters per minute, the turning delay is 10 second every time you pass a vertex.

Then B caught up with A in the second of departure.

10, solution: 250

The difficulty of this problem is that the delay when passing through each vertex is 10 second, and when B catches up with A, it will pass through 1 0 vertices more than A, which can be understood as 10 second for B to lead A..

Regardless of the turning delay time, if Party B leads Party A by 10 second, Party B will catch up with Party A: (100+60x1060 ÷ (90-60) =113 (min.

Now consider turning at each vertex: 330÷ 100=3 (times) ... 30 (meters),

* * * Time:113× 60+3×10 = 250 (seconds)

1 1. Calculate the following questions (4 points for each small question, *** 16 points).

( 1) (2)

= 1 12 ×4×4×6 = 6.5×23 -0.5

= 8 = 133 - 12

= 356

(3)

= 2÷0.2- 10

= 10- 10

= 0

(4)

= ( 1 14 +35 12 × 157 )÷ 154

= ( 1 14 +6 14 )÷ 154

= 152 ×4 15

= 2

12. Use an appropriate method to calculate the following questions (5 points for each small question, *** 15 points).

( 1) = 4 1.2×8. 1+ 1. 1×(80+ 12.5)+(4 1.2+ 12.5)× 1.9

=4 1.2×8. 1+ 1. 1×80+ 1. 1× 12.5+4 1.2× 1.9+ 12.5× 1.9

=4 1.2×(8. 1+ 1.9)+ 12.5×( 1. 1+ 1.9)+ 1. 1×80

=4 1.2× 10+ 12.5×3+ 1. 1×80

=4 12+37.5+88

=537.5

(2)

= 94 + 16 13 13 - 12 ÷358

= 29 12 ÷ 1 13 ÷358

= 29 12 ×34 ×829

= 12

(3)

= 64+32+ 16+8+4+2+ 1 128 ÷(2+4+8+ 16+32+64+ 128)

= 64+32+ 16+8+4+2+ 1 128 × 1 2×( 1+2+4+8+ 16+32+64)

= 1 128 × 12

= 1256

13. "Safety education, alarm bells are ringing". For this reason, a school randomly selected 200 students in the whole school to conduct a questionnaire survey on their understanding of safety knowledge, and then summarized and analyzed them according to the four categories of "very good", "very good", "average" and "poor" and drew a fan-shaped statistical chart.

(1) Complete the departmental statistical chart and calculate the number of 200 students who are "very familiar" with safety knowledge;

(2) Draw a bar chart.

Solution: 1-50%-25%-5% = 20%

200×25%=50 people

14. As shown in the figure, the side length of the square ABCD is 10 cm. Make a semicircle with CD as the diameter. E is the midpoint of the semicircle, and f is the midpoint of BC. Find the area of the shaded part in the figure (π is 3. 14).

Solution: If the parallel line with point E as AD intersects AB and G, then point G is the midpoint of AB side.

AG=GB= 10÷2=5 (cm), Ge = 10+00 ÷ 2 = 15 (cm), because F is the midpoint of BC and BF = 10 ÷.

Then the blank part s quadrilateral ABCD=S triangle age +s trapezoid BFEG

= 15×5÷2+(5+ 15)×5÷2

= 37.5+50

= 87.5 (square centimeter)

Shaded part S Yin = S Square ABCD+S Semicircle -S Quadrilateral ABCD