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fill (up) a vacancy

(11) .π (12)144 (13) 3 √ 2/4 (14) 0 (when n is even); 2 -n-3-n (when n is odd) (-n is a number)

( 15) (-∞，-2√2]U[2√2，+∞)

( 16) (0,2√3/3] ( 17) 264

Three answering questions

(18) (1) √ 10/4 (2) c = 4b = √ 6 or 2√6.

( 19)

ξ

0.5

0.7

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p

3/ 16

6/ 16

7/ 16

Eξ=3/4

(2) p (n = 2) = 3 (7/16) (3/16+6/16) 2 =1701/4096.

(20) (I)√3/3 (II) Let FM = x, and the projection of a' at the bottom is point O, then OA2+OM2=CM2, that is, the square solution of 8+(x+2) +4=64+(6-x) is x = 21/.

(2 1) (1) x-√2y- 1=0

(II) Let A(x 1, y1); B(x2，y2)，F 1(-c，0)，F2(c，0)，

G (X 1/3, Y 1/3) and H (X2/3, Y2/3) are obtained from the formula of barycentric coordinates. According to the meaning of the question, the origin o takes the line segment GH as the diameter.

In the circle of, the vector og.oh

After the linear equation is substituted into the curve equation, X 1x2 = (M4-4m2)/8 and Y 1Y2 = (m2-4)/8 can be obtained by using the relationship between roots and coefficients.

Replace x 1x2+y 1y2.

(22)(I)f '(X)=(X-a)ex[x2-(a-b-3)X+2 B- a-ab]

Let g(x)=x2+(b-a+3)x+2b-a-ab. According to the meaning of the question, there is g (a).

(2) let the two roots of the equation x2+(b-a+3)x+2b-a-ab=0 be x 1 x2, then x 1+x2 = a-b-3, x 1x2 = 2b-a-ab,

The three extreme points of the function f(x) are x 1 a x2.

① if x 1 a x2 x4 or x4 x 1 a x2 becomes arithmetic progression, both of them have x 1+x2 =2a.

B=-a-3, and the two substitutes in the equation are x 1=a-√6, and x2=a+√6, so X4 = a 2√ 6.

② if X 1x4x2 or X 1x4x2 becomes arithmetic progression, both of them have x 1+x2=a+x4.

X4 =-b-3, x 1x2 = (-2b-6-a) (2a+b+3), combined with the previous x 1x2=2b-a-ab, we can get b =-a+(-7 √13).

After doing it, I feel that the amount of thinking about the test questions is small, and I will know how to do it after reading the questions. It takes a lot of time to calculate, especially the image method of multiple-choice question 10 and the classification and counting of the seventeenth question in the fill-in-the-blank question. On the contrary, the solution is simple, and the first four solutions are simple in thinking and calculation. The last question, simple thinking, takes time to calculate. It took me 1 hour and 37 minutes to do this problem. ) Of course, there will be some problems. Please give us your guidance.