Current location - Training Enrollment Network - Mathematics courses - Mathematics Elective Course 4-4 Page 26 Question
Mathematics Elective Course 4-4 Page 26 Question
Connect ab, af and fc.

Arc AB= arc AF push-out angle AFB= angle ABF.

And because the angle is not good+angle ABF+ angle FBD = 90°, it is perpendicular to BC from AD.

Because arc AB+ arc AF+ arc fc = 90,

So angle Abe+angle AFB+ angle FBC=90 degrees.

So: angle BAD= angle AFB, so: angle BAE= angle ABE: AE=BE.

Best answer

Hoo hoo ~ ~