The intersection with the X axis is y=0, and there are 1 intersections of B 2-4ac = 0, and the two intersections are B 2-4ac > 0.

No intersection is b 2-4ac.

Then: Solve m 2-4 * (1) (-m+2).

=m^2-4m+8

=m^2-4m+4+4

=(m-2)^2+4

Because (m-2) 2 can't be negative, (m-2) 2+4 >; 0

Then the image of this parabola has two intersections with the x axis.