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Mixed Mathematics Problems of Candy
Solution: Let's assume that the price per kilogram of two kinds of fruits is X yuan and Y yuan respectively.

It is known that the ratio of A to B is 5: 4, and the price per kilogram is 30 yuan.

So among the 9 kilograms of mixed candy, there are 5 kilograms of candy A and 4 kilograms of candy B.

So 5x+4y=9*30 (1)

According to the ratio of A: B =3:2, the price per kilogram is 29 yuan.

Then there are 3 kilograms of candy A and 2 kilograms of candy B among the 5 kilograms of candy matched in this way.

So 3x+2y=5*29 (2)

(2)-( 1) * 2 Available:

x=290-270=20

Y=( 145-60)/2=42.5。

Therefore, the price of candy A per kilogram is 20 yuan; B candy is 45.5 yuan per kilogram.