When the plane leaves, the train has already left (that is, the distance between the plane and the train): 60× 12 = 720 (km).

To catch up with this distance, the plane is faster than the train: 60× (7- 1) = 360 (km/h).

So, by the time we catch up, the plane has already left: 720/360 = 2 (hours)

Two hours later, the train went again: 60× 2 = 120 (km).

Distance between two cities: (120+720) × 2 =1680 (km)

Second, the topic should be "The speed of B train is 36 kilometers per hour, and it will catch up with A train after 5 hours". If the speed of car A is 30 kilometers per hour, when will it become 36 kilometers per hour? You can't count without a hukou.

Car B overtook car A: 36× 5 = 180 (km)

At this time, a car has done it: 180/30 = 6 (hours)

So the A train is ahead of schedule: 6-5 = 1 (hours).

Third,

There are more trains in bilibili than in Station A: 10× 2 = 20 (km).

This is because the bus is faster than the local train every hour: 60-55 = 5 (km/h).

Go your separate ways when you meet: 20/5 = 4 (hours)

Therefore, the distance between the two stations is (60+55) × 4 = 460 (km).