(1) If a=0, the original inequality becomes 0 >: X+ 1, x <-1. It meets the conditions.

(2) if a is not equal to 0, ax-a >；; X+ 1-2a, move to x (1-a) < a- 1

When a= 1, the inequality is 0

When a< is 1 and 1-a is greater than 0, the inequality becomes X.

When a> 1, 1-a is less than 0 and inequality X >；; (a- 1)\( 1-a) is x>- 1, (two sides of inequality are divided by negative numbers to change direction), which does not meet the condition.

All in all, one

Note that it cannot be directly converted to X.