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Math problem (inequality) in junior one.
1. solution: we can know 1-m from point p in the second quadrant.

M> 1.

Then m-1>; 0, the solution set of inequality is x >;; 1-m/m- 1=- 1。

2. Solution: a≤x≤2 can be obtained by solving the inequality group.

Because the inequality group has no integer solution, a >;; 2.

3. Solution: A

Judging from the meaning of the question, the value of any x is not within the range of 2 ≤ x < 5.

So: A+ 1

4. solution: the solution of the inequality group can be obtained: a ≤ x.

From the meaning of the question, the inequality group has only four integer solutions, so the four integer solutions of x are 1, 0,-1, -2,

So -3≤a≤-2。

5. Solution: There is a problem that the intersection of two expressions is empty, so m+ 1≤2m- 1 can be solved as m≥2.

It is suggested that the landlord should develop the habit of drawing the number axis when solving such inequalities and set problems. Some problems seem complicated. If you draw a number axis according to the meaning of the question, it will be clear at a glance and the problem will be solved.

We can discuss it more later.