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Urgent for the answer to the 63-page exercise of compulsory mathematics in senior one! ! !
As shown in the figure: connecting AF

△ Is there CF‖BG in △ACF? Because the straight lines of two parallel planes cut by plane ACF are parallel

AB:BC=AG:GF

△AFD is the same.

AG:GF=DE:EF

So I have to prove it.

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