Suppose A(2pt squared, 2pt) and B(2ps squared, 2ps), then the product of the number of oa and ob is 0, namely 4p squared, t squared, s squared +4p squared, and ts=0, so ts=- 1.

And the square of oa =(2pt square) +(2pt square) = 4pt square *(t square+1)= 1,

The square of Ob = the square of 4p's square of s * (the square of s+1)=64.

Divide the two formulas to get t square = 1/4 (because st=- 1), and then substitute to get p square =4/5. In this way, you can write the answer.