2( 1/X)+[( 1/X)+( 1/X)](X-2-2)= 1

The solution is X=6.

X=6 is the solution of the original equation.

A: X=6.

Detailed explanation: Our great math teacher once said that if the workload is not clearly pointed out, it can be set to 1, A plans to finish in X days, and the work efficiency is (1/X), and B is the same as A, so it is also (1/X), so A's two-day independent work is 2 (/kloc-0). Because Party A did it for two days and finally finished it two days ahead of schedule, the cooperation between Party A and Party B is (X-2-2) days. Multiply the work efficiency and list the equation.

Please correct me if there are any mistakes. First, don't be too violent.